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No.19,thanks

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birdbird
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[email protected] 發表於 18-10-22 22:10
No.19,thanks

let x be the smaller number
(x+3) be the larger number.

5(x+3) > = 2x + 45
5x - 2x >= 45 -15
3x > = 30
x >= 10

As x is a multiple of 3, the min value of x is 12.

the min vales of the two numbers are 12 and 15.
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birdbird 發表於 18-10-22 22:19
let x be the smaller number
(x+3) be the larger number.

thank you very much.
Jasmine-4711
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本帖最後由 Jasmine-4711 於 18-10-22 23:03 編輯

回覆 [email protected] 的帖子

let nbe the first multiple of 3, the consecutive multiple is X+3 5x (n+3)>/=2n+455n+15 is more than orequal to 2n+453n+15 >/=453n>/=45-15n=10 (agree with you up to this part)
n is a multiple of 3 but 10 is not, so the smallest possible number (LCM)is 30
the larger possible number is 30+3=33
birdbird
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Jasmine-4711 發表於 18-10-22 22:53
回覆 [email protected] 的帖子

let nbe the first multiple of 3, the consecutive multiple is X+3 5x (n+ ...

n >= 10,
n is a multiple of 3, how come the LCM of 3 and 10 = min value of n???

一個數字 的值是10或以上, 而該数字是3的倍数, 數字的最小值是???
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birdbird 發表於 18-10-22 22:19
let x be the smaller number
(x+3) be the larger number.

Yr anwser is correct.thanks.
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